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There are a number of possible solutions.

Off the top of my head, one relatively simple method that's easy to understand would be to set up a few calculators.

Use the calculator's 'Minimum of' function to output the minimum of two inputs.

Then you'd check

* [Minimum of (P1 vs P2)]

* [Minimum of (P3 vs P4)]

Then you'd take these two outputs to a third calculator to work out the minimum of both of these - and that's the best time.

Then you could test each of the four players to see which of them has a time that is equal to the best time.